12x^2+196=112x

Solution for 12x^2+196=112x equation:

12x^2+196=112x

We move all terms to the left:

12x^2+196-(112x)=0

a = 12; b = -112; c = +196;
Δ = b2-4ac
Δ = -1122-4·12·196
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-56}{2*12}=\frac{56}{24}
=2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+56}{2*12}=\frac{168}{24}
=7
$